# SHL off campus coding Questions

## Question:

The company digital secure data transfer solutions provides data encryption and data sharing services. Their process uses a key K for encryption when transmitting a number. To encrypt a number, each digit in the number is replaced by the Kth digit after it in the number. The series of digits is considered in a cyclic fashion for the last K digits.

write an algorithm to find the encrypted number.

Input:

The first line consists of the input as an integer data representing the number. The second line consists of an integer and key, representing the key (K).

Output:

print an integer representing the encrypted number.

Examples:

input:

25143

3

output:

43251

Explanation:

Replace 2 with 4, 5 with 3, 1 with 2, 4 with 5 and 3 with 1. so the output will be 43251

### Algoritm to solve

1. Take all inputs from user , integer N and Key value.
2. First convert integer to arraylist
3. Then convert arraylist to array.
4. Then “Rotate array ” towards right side by “key-1” time to get the new array.
5. Now convert array to string type and return the answer as 43251

JAVA Implementation

```package arrayproblems;
import java.util.ArrayList;
class Problem21 {
public static void main(String[] args) {
int N=25143;
int key=3;
String res="";
ArrayList array1=new ArrayList();

while(N!=0) {
N=N/10;
}

int[] array2=new int[array1.size()];

int k=0;

for(int i=array1.size()-1;i>=0;i--) {

array2[k]=(int) array1.get(i);
k=k+1;
}

for(int j=0;j<key-1;j++) {

int temp=array2[array2.length-1];

for(int i=array2.length-1;i>=1;i--) {

array2[i]=array2[i-1];
}
array2[0]=temp;
}

for(int i:array2) {
System.out.print(i+res);
}

}
}
```

Watch step by step explanation for above code below

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