# Off Campus Coding Question on Arrays

Question: You are given a list of integers of size N. Write an algorithm to sort the first K elements (from list[0] to list[k-1] of the list in ascending order and the remaining (list[k] to list[k-1]) elements in decending order.

Input:

The first line of the input consists of an integer – inputlist_size, representing the number of elements in the list (N). The next line consists of N space separated integers representing the elements of the list. The last line consists of an integer num, representing the number of elements to be sorted in ascending order (K).

Output:

Print N space-separated integers representing the sorted list.

Constraints:

num<=inputlist_size

Examples:

Input:

8

11,7,5,10,46,23,16,8

3

Output:

5,7,11,46,23,16,10,8

Algorithm to Solve

• Take the input from user like number of array Elements, array elements and K value (upto which we want in ascending order).
• Later use two for loops for iterating through elements of array.
• inside second for loop use two condidtions
1. If the outer loop value is <= K , then write logic to sort in ascending order
2. If outer loop value is >k, then write logic to sort in decending order.
• Later return the sorted array

JAVA Code

```package arrayPrograms;

public class vrashi {

public static void main(String[] args) {

// coded by VRASHIKESH PATIL

int N=8;
int[] array1= {11,7,5,10,46,23,16,8};

int num=3;

for(int i=0;i<array1.length;i++) {

if(i<num) {
for(int j=i+1;j<num;j++) {

if(array1[i]>array1[j]) {
int temp=array1[j];
array1[j]=array1[i];
array1[i]=temp;
}
}
}
else if(i>num){
for(int j=num;j<array1.length;j++) {
if(array1[i]>array1[j]) {
int temp=array1[j];
array1[j]=array1[i];
array1[i]=temp;

}
}

}
}
for(int i:array1) {
System.out.print(i+" ");
}

}

}
```

Watch Complete Explanation for Above Code

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