HACKER EARTH off Campus Coding Question

School Renovation: Alice and Bob want to renovate and old school in his city. There are N classrooms in a school and ith classroom have a capacity of A[i] students. Bob is a builder and follows the instruction of alice.

Alice gives Q instructions of the following type

  • 1L: Move L classrooms Left
  • 2R: Move R classrooms Right
  • 3XY: Remove the next classroom and add new classrooms of capacity X and Y respectively to the right of the current classroom.(after performing this operation classroom number changes accordingly).

Note: The queries are always valid


Initially Bob is in ith classroom after performing all instructions of alice, print the capacity of all classroom from 1 to total classrooms.



N=5 , Q=2



Initially, class_no=1

APPSIAN off campus coding question


  • Alice instructs him to go right by 3 classrooms so class_no=(1+3)=4
  • Now he has to remove the next classroom so new A will be {1,2,3,4} and he has to add two classrooms with capacites of 2 and 6 so the new A will be {1,2,3,4,2,6} and class_no=4.

Input Format:

  • The first line contains two space seperated integers N,Q denoting the initial number of classrooms and the number of instructions.
  • The second line contains N space separated integers denoting initial classroom capacity .
  • Next Q lines contain queries of the form
    1. 1L
    2. 2R
    3. 3XY

Output Format:

After performing all instructions of alice, print the capacity of all classrooms from 1 to k (k- total number of the classroom in renovated classroom).


N=5 , Q=4





Algorithm to Solve:

  • Initially take every input from user like values of N,Q,A,queries
  • Then convert array A to “ArrayList” type (as we need to grow arraylist size in future).
  • Then use 2 outer for loops for iterating through elements of 2D array.
  • Inside for loops have 3 if conditions each for 1 , 2, 3.
  • Then according perform the tasks as mentioned in problem like if initial number in query is 1 then move class_no pointer towards left by specified positions.
  • Similarly do same thing for other queries as well.
  • At the end if first element in query is 3 then remove the next element of class_no pointer and add two elements in that position.
  • Finally print an array of elements representing final capacity of classrooms.


package arrayproblems;
import java.util.ArrayList;
class Problem22 {
	public static void main(String[] args) {
		// written by VRASHIKESH PATL 
		int N=5;
		int Q=4;
		int[] array1= {1,2,3,4,5};
		int[][] array2= {{2,3},{3,1,1},{1,2},{3,5,7}};
		int class_no=1;
		ArrayList array3=new ArrayList();
		for(int i=0;i<array1.length;i++) {
		for(int i=0;i<array2.length;i++) {
			for(int j=0;j<array2[i].length;j++) {
				if(array2[i][j]==1) {
				else if(array2[i][j]==2) {
				else if(array2[i][j]==3) {
					array3.add(class_no, array2[i][j+1]);
					array3.add(class_no+1, array2[i][j+2]);
		for(int i=0;i<array3.size();i++) {
			System.out.print(array3.get(i)+" ");

Watch Step by Step Explanation for Above Code

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